# LeetCode — Check if Array is sorted and rotated

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Given an array `nums`, return `true` if the array was originally sorted in non-decreasing order, then rotated some number of positions (including zero). Otherwise, return `false`.

There may be duplicates in the original array.

Note: An array `A` rotated by `x` positions results in an array `B` of the same length such that `A[i] == B[(i+x) % A.length]`, where `%` is the modulo operation.

Example 1:

`Input: nums = [3,4,5,1,2]Output: trueExplanation: [1,2,3,4,5] is the original sorted array.You can rotate the array by x = 3 positions to begin on the the element of value 3: [3,4,5,1,2].`

Example 2:

`Input: nums = [2,1,3,4]Output: falseExplanation: There is no sorted array once rotated that can make nums.`

Example 3:

`Input: nums = [1,2,3]Output: trueExplanation: [1,2,3] is the original sorted array.You can rotate the array by x = 0 positions (i.e. no rotation) to make nums.`

Example 4:

`Input: nums = [1,1,1]Output: trueExplanation: [1,1,1] is the original sorted array.You can rotate any number of positions to make nums.`

Example 5:

`Input: nums = [2,1]Output: trueExplanation: [1,2] is the original sorted array.You can rotate the array by x = 5 positions to begin on the element of value 2: [2,1].`

Constraints:

• `1 <= nums.length <= 100`
• `1 <= nums[i] <= 100`

Solution: