# LeetCode — Shifting Letters

You are given a string `s` of lowercase English letters and an integer array `shifts` of the same length.

Call the `shift()` of a letter, the next letter in the alphabet, (wrapping around so that `'z'` becomes `'a'`).

• For example, `shift('a') = 'b'`, `shift('t') = 'u'`, and `shift('z') = 'a'`.

Now for each `shifts[i] = x`, we want to shift the first `i + 1` letters of `s`, `x` times.

Return the final string after all such shifts to s are applied.

Example 1:

`Input: s = "abc", shifts = [3,5,9]Output: "rpl"Explanation: We start with "abc".After shifting the first 1 letters of s by 3, we have "dbc".After shifting the first 2 letters of s by 5, we have "igc".After shifting the first 3 letters of s by 9, we have "rpl", the answer.`

Example 2:

`Input: s = "aaa", shifts = [1,2,3]Output: "gfd"`

Constraints:

• `1 <= s.length <= 105`
• `s` consists of lowercase English letters.
• `shifts.length == s.length`
• `0 <= shifts[i] <= 109`

Solution:

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